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Multiple Choice

How many cases of #10 cans of green beans are required to serve 285 (½ cup) portions?

To determine how many cases of #10 cans of green beans are needed to serve 285 half-cup portions, it's essential to know the yield of a #10 can. Typically, a #10 can contains approximately 12 to 13 cups of food. For the sake of this calculation, let's use the middle figure of 12 cups per can. First, convert the number of half-cup portions into cups. Since each portion is ½ cup, you would multiply the total number of portions (285) by the volume of each portion in cups. This results in: 285 portions × 0.5 cups/portion = 142.5 cups Next, to find out how many #10 cans are required to get 142.5 cups, divide the total cups needed by the number of cups in one can: 142.5 cups ÷ 12 cups/can = 11.875 cans Since you cannot purchase a fraction of a can, you'll need to round up to the next whole number, which indicates that you require 12 cans in total. Now, considering how many cases of #10 cans are necessary, it is beneficial to know that a standard case contains 6 #10 cans. Therefore, dividing the

To determine how many cases of #10 cans of green beans are needed to serve 285 half-cup portions, it's essential to know the yield of a #10 can. Typically, a #10 can contains approximately 12 to 13 cups of food. For the sake of this calculation, let's use the middle figure of 12 cups per can.

First, convert the number of half-cup portions into cups. Since each portion is ½ cup, you would multiply the total number of portions (285) by the volume of each portion in cups. This results in:

285 portions × 0.5 cups/portion = 142.5 cups

Next, to find out how many #10 cans are required to get 142.5 cups, divide the total cups needed by the number of cups in one can:

142.5 cups ÷ 12 cups/can = 11.875 cans

Since you cannot purchase a fraction of a can, you'll need to round up to the next whole number, which indicates that you require 12 cans in total.

Now, considering how many cases of #10 cans are necessary, it is beneficial to know that a standard case contains 6 #10 cans. Therefore, dividing the